python火柴人打架代码？
以下是一个简单的Python火柴人打架代码，可以通过键盘输入控制火柴人的动作：
三d火柴人游戏_火柴人三人游戏大全
三d火柴人游戏_火柴人三人游戏大全
三d火柴人游戏_火柴人三人游戏大全
import py
# 初始化Py
py.init()
# 设置屏幕大小和标题
screen_width = 800
screen_height = 600
screen = py.display.set_mode((screen_width, screen_height))
py.display.set_caption("火柴人大战")
# 加载火柴人
stickman_image = py.image.load("stickman.png")
stickman_rect = stickman_image.get_rect()
stickman_speed = 5
# 设置火柴人的初始位置和方向
stickman_x = screen_width // 2
stickman_y = screen_height // 2
stickman_direction = "right"
# 游戏循环
running = True
while running:
for nt in py.nt.get():
if nt.type == py.QUIT:
running = False
# 处理用户输入
keys = py.key.get_pressed()
if keys[py.K_LEFT]:
stickman_direction = "left"
stickman_x -= stickman_speed
elif keys[py.K_RIGHT]:
stickman_direction = "right"
stickman_x += stickman_speed
elif keys[py.K_UP]:
stickman_direction = "up"
stickman_y -= stickman_speed
elif keys[py.K_DOWN]:
stickman_direction = "down"
stickman_y += stickman_speed
# 绘制火柴人
screen.fill((255, 255, 255))
if stickman_direction == "right":
screen.blit(stickman_image, (stickman_x, stickman_y))
elif stickman_direction == "left":
flipped_stickman = py.transform.flip(stickman_image, True, False)
screen.blit(flipped_stickman, (stickman_x, stickman_y))
elif stickman_direction == "up":
rotated_stickman = py.transform.rotate(stickman_image, 90)
screen.blit(rotated_stickman, (stickman_x, stickman_y))
elif stickman_direction == "down":
rotated_stickman = py.transform.rotate(stickman_image, -90)
screen.blit(rotated_stickman, (stickman_x, stickman_y))
# 更新屏幕
py.display.update()
# 退出Py
py.quit()
在这个游戏中，火柴人可以向左、右、上、下移动，并根据方向旋转或翻转。你需要将代码中的“stickman.png”替换为你自己的火柴人。